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Razavi Basic Circuits Lec 24: Inductor Circuits

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greetings welcome to lecture number 24

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on basic circuit theory i am bashar zavi

1:32

today we will continue to look at

1:35

inductors and their properties

1:38

and understand how

1:40

inductors respond to for example current

1:44

inputs or voltage inputs

1:46

as

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examples of very simple circuits

1:50

and then

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we will look at some other properties of

1:53

inductors that also are interesting as

1:56

far as circuit analysis and design are

1:59

concerned

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and finally if we have time we will

2:02

begin to look at our first

2:05

simple rl circuit to see how it operates

2:08

and how we go about analyzing it

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but before we go there let's take a look

2:14

at what we covered last time

2:16

so we started by introducing the concept

2:20

of inductance

2:21

and inductors and we saw that

2:24

the original observation by faraday was

2:27

that if we have a

2:29

wire

2:30

carrying a current

2:32

and hence generating a magnetic field

2:34

around it according to the right hand

2:36

rule

2:38

and if this current changes with time

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which means the magnetic field changes

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with time

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then this time varying magnetic field

2:48

can induce a voltage

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on a for example separate piece of wire

2:54

so if i place a wire here this red wire

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i can measure voltage here even though

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there is no current passing through the

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red wire

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so it's a fascinating effect and it's

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certainly not ohm's law

3:07

but then we tried to extend this idea

3:09

and we said that even if you have a

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single wire

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carrying a time varying current and

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experiencing its own time-varying

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magnetic field then that wire also must

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generate a voltage across it because

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of faraday's law

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so we would expect that the voltage will

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be generated here even though this wire

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has no resistance so again this is not

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not ohm's law

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so this is something that we call

3:38

self-inductance or just an inductor

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and of course a simple piece of wire

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will not be a very good inductor so we

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typically wind it in some form

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like what we saw last time in this form

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and that allows us to have more

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inductance for a given length or even

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volume etc

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so for such a device which we call an

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inductor we have a current a voltage and

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an inductance and these three are

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related by this equation the voltage

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that we generate across this inductor

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is proportional to how fast

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the current through the inductor is

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changing with time

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multiplied by l1 of course

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so this equation

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of course has to be observed with

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respect to

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the polarities that we have here so if

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the current is flowing from high

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potential to low potential

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then there's a plus sign here if the

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current is going from low potential to

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high potential then there's a minus sign

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here

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all right but this equation also tells

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us some interesting things about

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the behavior of inductors

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for example when there's a switching

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event going on something is wants to

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change suddenly the inductor has a

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certain behavior

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what we know is that if the voltage that

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is available for this inductor from the

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rest of the circuit

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is less than infinity

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then this derivative has to be less than

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infinity that means that the current

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through this inductor cannot jump

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instantaneously

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and that's the key property of inductors

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they resist

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the change of index and the change of

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current they don't want the current to

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change too fast

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on the other hand if we go to an extreme

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condition where

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the

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current through an inductor

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has become constant so let's say this is

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inside a big circuit and eventually all

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the

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transients have died away and we have a

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constant current through the inductor

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and then we know that the voltage across

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the inductor will be zero

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and a device that guarantees a zero volt

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difference between these terminals is a

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short circuit so that becomes a short

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circuit

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so these two cases are important to

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remember because they often happen in

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our transient analysis of circuits

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okay and one last point was

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that the initial condition

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that we can specify for an inductor is a

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current through it another voltage

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across it fundamentally it's the current

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through the inductor that can serve as

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what gives the inductor energy and we

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will see that today

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remember for capacitors the initial

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condition was a voltage because the

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voltage that gives the capacitor energy

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one-half cv squared so we will see

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something similar in terms of current

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and inductance and the energy stored

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in the magnetic field of this inductor

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all right one last point uh last time i

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said that

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this is an inductor right it's an

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inductor and when i started out i said

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this is not an inductor because just a

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piece of wire and it satisfies ohm's law

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and so on

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now these this doesn't seem quite to

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agree with what i just said here right

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so is this an inductor is it not an

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inductor we have to decide right this is

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a piece of wire

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well strictly speaking even a piece of

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wire has inductance so the inductance

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from here to is not zero even though it

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looks like a straight piece of wire and

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even though it may have no resistance at

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all but for our analysis we assume that

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you have a piece of wire is ideal it's

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like a short circuit it has zeros

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resistance and zero inductance

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but if you want to build an inductor

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then of course we wind it and all that

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okay just to avoid any confusion

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so in our studies we typically assume

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that a piece of a straight piece of wire

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does not have an inductance or its

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inductance is negligible

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all right so

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let's go and

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look at

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some more examples

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of

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simple inductors

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so here's a another example that we have

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here

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okay so

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last time we

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had a situation

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where we had a

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current source

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feeding

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a an inductor

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like so

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call this i1 and l1

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and we're trying to plot this voltage

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here

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right if you remember and the current

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source was

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a ramp last time so this time we'll make

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it a little more interesting so suppose

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i1 looks like this as a function of time

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so i1 as a function of time

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is 0 before time zero

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and then it looks like a ramp so it goes

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up

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for some time

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and then at

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some time t1

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it becomes constant

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and then at some point t2

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it uh

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falls linearly back to zero

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okay and it reaches zero at time t3

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so this is a current waveform that i

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have managed to generate by this current

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source is pushing this current through

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the inductor and i would like to find

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the corresponding output voltage

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now i know that the voltage across an

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inductor is given by this equation so i

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just need to take the derivative of this

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waveform to obtain the voltage and of

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course multiply by l

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so i will say

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that

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v out

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the voltage across the inductor is given

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by the derivative of all of this so we

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see that

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before times zero

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we have a constant value with zero

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anyway so that's zero

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at this point we have a certain slope so

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let's call that slope alpha

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so this jumps to

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alpha times l

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right the derivative times l

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and this slope is constant up to t1

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from t1 to t2 the slope is zero so the

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voltage across the inductor is zero

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so this voltage jumps to zero

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and then at t2

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we have

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a negative slope so let's call that

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beta

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so

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this slope is multiplied by l to give us

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the voltage across the inductor

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so now this will be like this

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this value is beta l

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and this goes on until

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t3

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okay so this is the overall

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shape that we have now let's say that

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this goes back to zero from here on just

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for simplicity so this also

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goes to zero like that

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so the voltage waveform across the

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inductor looks like this

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all right it's just the derivative of

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the current waveform that's passing

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through the inductor

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all right so that's simple enough but uh

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let's try to see what happens as we go

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to some extreme case

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if i

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make these transitions faster

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what happens so suppose

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this transition happens in a much

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shorter time so something like that

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and similarly this transition happens in

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much shorter time like this

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so then what happens the voltage

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waveforms well they're proportional to

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the slope

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so this voltage waveform which is alpha

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alpha is now much bigger

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so this height will be greater so we'll

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be for example here

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and of course it lasts

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let's say it lasts up to here to this

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little time here so it lasts for a

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shorter amount of time

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right only from here to here past this

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point the current is constant

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and then this goes on

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up to

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right here at this point

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and at this point we're dropping at a

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faster rate so the voltage is larger but

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more negative

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so the voltage will be like this

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and this lasts up to this point here

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so it goes back and stays

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at zero

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so we see that as the slope

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of these transitions increases

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the

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pulse that we have generated here

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becomes narrower and taller both here

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and here

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so in the limit

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if this transition is infinitely fast

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what do we get here

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this becomes infinitely narrow and

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infinitely tall so it becomes an impulse

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so in the limit if the current jumps

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here and jumps here that requires that

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we have an impulsive voltage here and an

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impossible voltage here

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if the circuit surrounded this inductor

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over here is capable of

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the

13:02

sustaining an infinite voltage then it's

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fine we can do that

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and in other words if this current

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source really can do something like this

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if it can jump from some zero to some

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amount in zero time yes we do get a very

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high voltage across the inductor and in

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fact this is a problem

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in some circuits that can damage some

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circuits and we'll talk about that later

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all right so that was one little example

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let's go to another example

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and see what we have here

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so suppose i have a

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voltage source

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which we call v in

13:43

and i have directly

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connected this to an inductor

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l1

13:51

and i am interested in this current

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as a function of time

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if this voltage has the following shape

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so

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let's plot v in as a function of time

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so our input or our stimulus

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is uh given by something like this v in

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initially is zero before times 0 then it

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grows linearly with time with the slope

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of

14:19

alpha

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up to some point t1

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t1 and then stays constant past that

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point

14:31

all right

14:32

so this time i'm applying a voltage

14:34

across the inductor previously i was

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applying a current through the inductor

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and the voltage has a ramp section and

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then a flat section and i would like to

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find the current resulting from this

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voltage input

14:49

okay so what we know is that the current

14:52

across this equation is the integral of

14:55

the voltage and then divided by the

14:56

inductance so we have to integrate this

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so let's say this is alpha t here

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so we say the current i in

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is 1 over l

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1

15:09

integral of

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alpha t

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dt

15:15

this is for zero to t1 right so from

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zero to t

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and for t

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between zero

15:25

and t1

15:28

that's the equation that we have for the

15:29

current passing through the inductor in

15:33

response to this ramp voltage

15:35

okay so that comes out to

15:38

be uh alpha over l1

15:42

times t squared

15:45

our assumption is that there is no

15:47

initial current in the inductor if there

15:50

were then we'd have to add that at that

15:52

here because that would be

15:54

an integration constant that you would

15:55

have to include but right now we assume

15:58

there's no initial condition

16:00

okay so this is the current waveform

16:03

passing through the inductor

16:05

between zero and t1

16:08

so let's try to plot that for now and

16:11

then we need to see what happens after

16:14

t1

16:16

okay so here we go

16:22

i have i in

16:25

and then t

16:28

okay so this is a simple quadratic

16:30

so it goes hyperbolically parabolically

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up to

16:34

this point t1

16:36

it goes up parabolically

16:38

like this

16:42

okay

16:45

so the current is growing relatively

16:47

fast right parabolic with time

16:50

okay then what happens after t1

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after t1 the voltage has become constant

16:56

if the voltage is constant we have to

16:58

integrate properly

16:59

so now for

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t greater than t one

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we say

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i in

17:08

is equal to

17:10

one over l one

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so let's call this voltage something

17:16

call this a v1

17:18

so

17:19

that would be v1 times t

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because i am integrating

17:26

v

17:27

out of v times dt and v is given by v1 a

17:32

constant value so it comes out of the

17:34

integral and it just just gives me t

17:37

so beyond t1 the current still grows but

17:40

now linearly with time

17:42

so we have an equation of this form so

17:45

this is a straight line

17:48

and has a certain slope which is v1 over

17:52

l1

17:54

that is the behavior of the current that

17:56

flows through the inductor

18:02

so one thing that is particularly

18:04

interesting here is that the current

18:06

through the inductor

18:08

grows unbounded right it just goes to

18:11

infinity

18:12

and that sort of makes sense does it

18:15

make sense

18:16

well

18:17

when the vote is constant it's like you

18:19

have applied a battery across an

18:21

inductor

18:23

and what should happen the inductor

18:25

wants to draw more and more current so

18:26

the current just keeps going up and

18:28

going up as if the inductor wanted to

18:31

act as a short circuit right it's not

18:33

entirely true but intuitively that's

18:35

what would happen

18:37

all right

18:38

so

18:39

let's go on to another example

18:42

to see what happens here

18:45

so let's change the

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color of our pen

18:50

to green

18:52

look at another example here

18:58

okay so in this case we will consider

19:02

something very simple

19:04

we have

19:05

a battery

19:08

a resistor r1

19:11

an inductor l1

19:14

a voltage source vb

19:17

and we are interested to find this

19:19

current here

19:21

call it i1

19:25

all right very simple

19:27

our assumption is that this circuit has

19:28

been connected like so for a very long

19:31

time so all of the transients have died

19:34

away

19:35

there's no

19:36

time varying component anymore

19:39

so if there are any currents on any

19:40

voltages in the circuit they're all

19:42

constant

19:43

and we would like to find the current

19:45

that flows through the loop under that

19:47

condition

19:49

all right so what do we do

19:52

okay

19:53

so

19:54

we say that if everything has become

19:56

constant for example i1 has become

19:59

constant

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so we say

20:01

i1

20:04

is constant

20:07

that means

20:09

that

20:10

the inductor voltage vl1 is equal to

20:13

zero

20:16

right

20:18

the current doesn't change with time so

20:19

the voltage across the inductor is zero

20:22

if the voltage across the inductor is

20:24

zero

20:25

how much is the voltage across the

20:27

resistor

20:29

okay so this voltage is equal to this

20:32

voltage plus this voltage right so this

20:33

voltage is zero the voltage across r1 is

20:36

just the battery voltage

20:38

so this voltage here

20:41

is just vb

20:44

and because i have the voltage across

20:45

the resistor i can find this current so

20:48

that means that i1

20:50

is equal to

20:52

vb

20:53

over r1

20:56

okay very simple

20:59

all right the purpose of this example is

21:01

to show you

21:02

how we can create

21:04

an initial condition in an inductor

21:07

before we start doing something with

21:09

that inductor

21:10

so if you wanted to create an initial

21:12

current through the inductor you would

21:13

hook it up like this to a resistor to a

21:16

battery you adjust the value of the

21:18

resistor to give us the current that we

21:20

need or the battery and the resistor

21:21

right and then this inductor is ready it

21:24

has certain current in it now we can

21:26

switch it out of here switch into

21:28

something else etc and those are things

21:30

that we'll see later

21:32

but this is a very simple example of

21:34

creating

21:35

a known current through an inductor

21:39

all right

21:40

let's go to another example

21:44

and

21:46

make it a little more interesting

21:48

so let me do this

21:53

all right so we found this current in

21:55

the circuit right

21:56

now i'm going to add

21:59

a resistor here r2

22:06

okay

22:07

so we'll still keep this current call

22:09

this current i1 i like before

22:14

and the question is

22:16

is the red i1 different from the green

22:19

i1 now that i have added this resistor

22:22

r2

22:24

so i'll think about it and see again

22:26

we're assuming that a circuit was built

22:27

a long time ago all the transients have

22:30

died away everything is constant

22:34

okay well

22:37

what we see is that because the current

22:39

through the inductor is constant

22:41

whatever it is it may not be i1 but

22:43

whatever it is constant right

22:45

so we say

22:46

a current

22:50

through

22:51

l1 is constant

22:55

and again this is because the circuit

22:58

was built a long time ago and all these

23:00

transients have decayed have gone away

23:03

right

23:04

okay so if the current through l1 is

23:05

constant

23:07

we know that the voltage has to be zero

23:09

across the inductor no other way right

23:12

so we say v l1 is equal to zero

23:17

if the voltage across the inductor is

23:19

zero how much is the voltage across r2

23:22

well that's also zero they're in

23:24

parallel

23:25

so how much is the current through r2

23:27

that's also zero

23:29

so we say vr2

23:32

equals zero which means

23:35

current

23:38

through

23:39

r2 is zero

23:42

so this current is zero this connection

23:44

this current is zero right this current

23:46

is zero

23:47

okay if the current through r2 is zero

23:50

and this current i1 is coming in where

23:52

would it go

23:54

it cannot go this way it has to go

23:56

through the inductor right

23:57

so because the current through r2 is

23:59

zero

24:00

all of

24:02

i1

24:04

must

24:06

flow

24:08

through

24:11

l1

24:14

all right

24:15

how much is i1 the red i1 well this

24:18

voltage is still zero right if this

24:20

voltage is zero and this side of r1 is

24:22

zero this side of r1 is vb so the

24:24

current to r1 is still vb over r1

24:28

so we say i1

24:30

is vb

24:33

minus 0 over r1 right

24:36

vb minus 0 over r1

24:39

okay so the current didn't change

24:41

so even though i brought another

24:42

resistor and placed it in parallel with

24:44

the inductor nothing really changing the

24:46

circuit as far as these initial

24:48

conditions are concerned

24:51

so

24:52

this is just because

24:55

if we have waited a long time and

24:57

the current run inductor is constant

25:00

it forces a zero volt difference across

25:03

it so it acts like a short circuit

25:06

so this is a short circuit and we have a

25:08

short circuit here and place a resistor

25:10

in parallel with it the short circuit

25:12

dominates right the resistor doesn't

25:14

have any role in the current division

25:16

between this and that

25:19

okay so that's

25:21

an extension of that example

25:24

[Music]

25:27

as you can imagine circuits and

25:29

electronics also have wide application

25:31

and robotics so here's an example that

25:34

is quite interesting

25:36

in this paper they deal with flapping

25:39

wing robotic insects so these are very

25:42

small insects that are robotic and they

25:45

can travel to different places and

25:47

collect information for example they can

25:50

fly over a

25:51

fire and collect information they can go

25:54

into the battlefield and collect

25:55

information etc

25:57

so they are very small and very

26:00

light in weight so here's the hand and

26:03

here's

26:03

the

26:05

the

26:06

flapping wing

26:07

a micro robot so you can imagine this

26:11

robot of course has to have electronics

26:13

in it to be able to fly and to be able

26:15

to collect information

26:18

in particular for these wings to flap

26:21

they need a

26:22

piezoelectric device that creates this

26:26

movement

26:27

and for that they need to generate a

26:29

voltage

26:30

and that's how the

26:33

they come up with this circuit

26:35

that takes a

26:37

battery voltage from here

26:39

and generates a high voltage that is

26:41

necessary for the piezoelectric device

26:44

on the far end

26:47

now there are a whole bunch of devices

26:48

in here we know some of them we know

26:50

switches and capacitors and inductors

26:53

when resistors we don't know these

26:55

devices these are called diodes these

26:57

are what you would study in electronics

27:00

courses

27:01

but we can see that there's a

27:03

great deal of what we have seen in this

27:05

course in terms of the devices and the

27:08

concepts that are also useful in an

27:11

application like this

27:13

when we are trying to generate for

27:14

example a high voltage very low voltage

27:16

or the other way around

27:18

so that is one application of

27:21

electronics and circuits in robotics

27:24

isn't that beautiful

27:30

now let's go

27:32

and find look at another example here

27:42

so i have a battery

27:45

vb

27:48

i have a switch

27:50

and then i have an inductor l one

27:54

and this which turns on at time zero

27:58

and would like to

27:59

plot this current i1

28:04

all right so as you can see the circuits

28:06

that we are considering right now are

28:07

very simple because we need to learn how

28:09

to walk before we start running and

28:12

that's the objective of all these very

28:14

simple situations

28:17

all right so

28:19

um the switch is not conducting is

28:22

open is off before time zero so the four

28:26

times zero there's nothing here

28:28

this inductor has no current no there's

28:30

no life everything is zero right so the

28:32

current is zero

28:34

this current is zero so we say

28:36

for t less than zero

28:39

i1 is equal to zero

28:44

right and then we turn the switch on it

28:46

starts conducting

28:49

okay

28:50

so how much is i1 at 0 plus

28:55

so

28:56

i1 at

28:58

0 plus

29:02

what we have to decide can i 1 jump

29:05

instantaneously from 0 minus to 0 plus

29:08

or not

29:09

if the only way for i want to jump

29:12

is

29:13

for this derivative to be infinite is

29:15

for the voltage available for the

29:17

inductor to be infinite

29:19

can the circuit deliver infinite

29:22

voltages inductors

29:23

no because this battery has some finite

29:25

amount 1.5 volts 5 volts something like

29:28

that so an infinite voltage is not

29:30

available here which means that the

29:32

current of the inductor cannot jump

29:34

instantaneously

29:36

which means the current through this

29:38

loop at time zero plus is still the same

29:42

as at at time zero minus

29:45

so that still has to be

29:47

zero

29:50

all right okay

29:52

so and then what happens

29:54

all right so then there's a current

29:55

flowing we have a battery a piece of

29:57

wire inductor and some current starts

29:59

flowing how do i calculate the current

30:01

not a problem i say from here right i

30:04

say

30:04

i1

30:07

is equal to 1 over l1

30:09

integral of vb

30:12

dt

30:13

vb is constant

30:15

so that's just vb

30:17

over l1 times

30:20

this so what we see is the following

30:24

you see that i one

30:26

as a function of time

30:29

was zero before time zero

30:31

right after zero and zero plus still has

30:33

to be zero according to the analysis we

30:36

just did and then past that point it's

30:38

just going up linearly so it's going to

30:40

go like this right

30:43

and this is of course not that much

30:45

different from this situation here we

30:47

had a constant voltage across an

30:49

inductor

30:50

from now on from t1 on and of course we

30:53

saw

30:54

a ramp

30:55

for the current generated through it

30:59

okay so that's a nice little example

31:02

that we have here

31:05

all right so

31:08

i think it's good to

31:10

summarize our findings so far

31:14

for

31:15

some of the properties of inductors

31:17

before we look at more properties

31:20

so we say

31:23

summary

31:27

we say with

31:30

a0

31:33

initial

31:37

actually let me

31:39

erase this

31:41

i have to put it somewhere else

31:43

okay so here's the summary and it is a

31:46

particular particular comparison i want

31:48

to

31:49

have between inductors and capacitors

31:53

so

31:56

all right so let's see here

31:59

okay so we say

32:01

inductors

32:06

and capacitors

32:17

so there are

32:18

uh four different cases depending on

32:20

whether we have an inductor or a

32:22

capacitor and whether

32:24

the voltages or currents are changing

32:26

rapidly or have stopped changing they're

32:28

constant okay so those are four cases

32:30

you want to consider

32:32

all right so we say

32:35

for inductors

32:39

we say if

32:43

v is less than infinity

32:46

right if the voltage that we can give to

32:49

the inductor from outside whatever it is

32:51

right the voltage that we can give the

32:53

inductor is not infinite and then the

32:56

current of the inductor cannot jump

32:58

instantaneously

33:00

so we say

33:02

i

33:04

can't

33:06

jump

33:10

right

33:11

so if

33:13

i is equal to 0

33:17

as 0 minus it will want to stay at 0 as

33:20

0 plus

33:22

so i equals zero

33:24

and if the current is zero

33:27

uh what does the inductor represent

33:30

we have an inductor

33:32

the inductor says my current shall be

33:34

zero

33:35

here and it shall be zero here

33:38

right that's what we decided

33:40

a car a device that wants to maintain a

33:43

zero current

33:45

what is it called

33:46

it's called an open circuit so we see

33:49

that the inductor is equivalent to an

33:52

open circuit

33:56

all right so just right around here the

33:59

inductor is acting as an open circuit

34:01

because the current through it cannot

34:02

change right away of course past that

34:04

point is different right because now we

34:06

are giving it time

34:08

for it for it to change its current but

34:10

right around that transient that

34:12

switching event whatever transition we

34:15

have the inductor acts as an open

34:17

circuit provided that it has a zero

34:20

current at time zero minus

34:25

okay

34:26

for capacitors what was the situation

34:29

well for capacitors was the other way

34:30

around we said that if the current

34:33

available

34:35

for a capacitor is not infinite

34:39

right so we have a capacitor we can

34:41

disconnect the rest of the circuit the

34:42

rest of circuit is not capable of giving

34:45

it infinite current then the voltage

34:47

across the capacitor cannot jump

34:50

so we said

34:52

v

34:53

can't

34:56

jump

35:01

so that means that if the voltage on the

35:02

capacitor is zero

35:04

at zero minus it has to be zero as zero

35:07

plus

35:08

so we say if the voltage is zero

35:12

it wants to maintain that zero voltage

35:14

for a little while

35:16

so it acts as a device that guarantees a

35:19

zero volt difference and such a device

35:22

is called a short circuit

35:24

so the capacitor

35:25

is equivalent to a short circuit

35:32

all right

35:34

so

35:35

so these

35:36

two cases correspond to situations where

35:40

we have some sort of

35:42

jump some sort of transient some sort of

35:44

switching event in a circuit and we're

35:47

looking at the circuit just before that

35:48

event and just after that event and

35:50

we're trying to decide what happens in

35:52

the circuit so these two are extremely

35:54

important for those cases

35:58

all right and then we have the other

36:00

extreme case where we have waited for

36:03

the circuit to settle all the transients

36:05

have died away and we would like to see

36:08

what role an inductor plays and what

36:11

role a capacitor plays

36:13

so for that lecture we decided that if

36:17

i is constant

36:22

right y is constant so we have waited a

36:24

long time like in here and the current

36:26

has to become constant if the current is

36:29

constant then the voltage is zero and

36:31

the only device that guarantees a zero

36:33

volt difference is a short circuit

36:36

so we say l

36:39

is equivalent to a

36:41

short circuit

36:47

and for capacitors we saw that it was

36:48

the other way around if the voltage on

36:51

the capacitor has become constant so we

36:54

have weighted all the transients have

36:55

died away and then c dv over dt is zero

36:58

so i is zero

37:00

all right when i is zero what kind of

37:03

device can guarantee a zero current

37:05

that would be an open circuit

37:07

so we say if

37:11

v is constant

37:15

then

37:18

the capacitor acts

37:20

as an open

37:27

okay so the first row is important when

37:30

there's a switching event some sort of

37:31

transient

37:33

and

37:34

the second row is important when we have

37:36

weighted we're trying to look for final

37:38

values in the circuit remember we always

37:40

want to look for y infinity right

37:42

there's a final value of a voltage or a

37:44

current or something so the second row

37:47

is handy for those cases

37:50

all right very good so

37:53

with this now we are ready to

37:55

go over some more

37:57

inductor properties so let's go

38:00

to the next page

38:03

see what we should do here

38:09

okay now

38:10

change the color

38:13

all right so the next property of

38:14

inductors that we're going to look at

38:16

is the energy

38:18

so energy in

38:21

inductors

38:28

so just a way we can store energy in the

38:31

electric field inside the capacitor so

38:35

we put some charge here some charge here

38:36

we got electric field we have energy

38:39

we can also store energy

38:41

in the magnetic field of an inductor so

38:44

if you have an inductor and i pass a

38:45

current through it it generates a

38:46

magnetic field that magnetic field

38:48

actually has energy in it

38:50

so to calculate the energy in an

38:52

inductor what we do is we start with the

38:54

definition of power remember we

38:56

calculate the power

38:58

as

39:00

v of v of t times

39:02

i of t this was true for any device

39:05

right it doesn't matter what it is

39:07

for any

39:08

any device any circuit we have a voltage

39:11

and we have a corresponding current the

39:13

product of these two tells us how much

39:15

power is going to that circuit

39:18

okay so let's do that

39:20

and here's

39:21

our good old inductor

39:24

i of t here

39:27

v of t here and l

39:30

you may be wondering why i'm using

39:31

lowercase here it doesn't matter

39:32

lowercase uppercase

39:34

and then i'm interested in energy and i

39:37

know that

39:38

energy

39:39

is integral of power

39:41

with respect to time

39:43

from sum 0 to some t

39:46

right so we'll go ahead and integrate

39:49

this

39:50

integral of 0 to t

39:52

p is v of t i of t now i know that for

39:55

an inductor

39:56

it just happens

39:58

that we have this

40:01

so why don't we replace for a v

40:03

from this equation into this equation

40:06

into this equation so i have

40:08

l d i over dt

40:12

times i times dt

40:16

okay and now you can see that what we

40:19

have here is

40:20

this l comes out you can cross this dt

40:23

with the cte and you have idi so that

40:25

equals one half of i squared

40:27

so we have one half of l

40:30

i squared of t

40:34

so the amount of energy stored in a an

40:37

inductor

40:38

is given by one half times the

40:40

inductance times the current at that

40:43

moment through the inductor

40:45

squared

40:47

for the capacitor we had one half cv

40:49

squared was one half times the

40:51

capacitance times the voltage across the

40:53

capacitor at that moment squared

40:56

okay so that's the simple equation that

40:58

we have

40:59

okay

41:00

so that's one little point that we need

41:02

to know

41:04

and the next property relates to

41:08

inductors in

41:11

series

41:15

so we have found the series combination

41:18

of resistors and capacitors etc so now

41:21

it makes sense to look at the series and

41:23

parallel combinations of inductors as

41:26

well

41:28

all right so another problem let's draw

41:31

a bunch of inductors here

41:34

l1 and 2

41:36

l3 it doesn't matter how many you draw

41:39

and i would like to find

41:41

the equivalent inductance right

41:43

this whole thing still has two terminals

41:46

so i can put in the black box and i can

41:48

say that

41:49

this black box has probably some

41:52

equivalent inductance

41:54

and the question is how much is that in

41:56

terms of l1 l2 l3 etc

42:01

all right another problem so ordinarily

42:03

what we do is we apply a voltage between

42:05

these two terminals we call it vx

42:08

and we have a current ix

42:12

if i can find vx in terms of ix or x

42:15

into the vx

42:16

and i can simplify that to

42:19

an equation that that resembles that of

42:22

inductors i can find the equivalent

42:24

inductance

42:27

okay

42:28

so

42:30

i have a current ix flowing through all

42:32

of these these are in series so by

42:34

definition they carry the same current

42:37

how much is this voltage from here to

42:39

here

42:40

the voltage across l1

42:43

well we know that the voltage russell

42:44

inductor is given by l

42:47

di over dt

42:48

and i is indeed going from high

42:51

potential to low potential so i do not

42:53

need a negative sign

42:56

so the voltage

42:58

across

42:59

l1 is

43:02

l1

43:03

dix

43:05

over dt

43:12

about the voltage across l2

43:14

same thing right so here you have l2

43:17

dix over dt and so on right

43:24

so i found this voltage i found this

43:26

voltage i found this voltage and so on

43:28

now i can write the kvl i can say this

43:30

voltage

43:32

is equal to this plus this plus this etc

43:35

so i can say

43:36

around the kdl

43:38

we have vx

43:40

is equal to

43:42

l1 dix

43:44

over dt

43:46

plus l2 dix

43:49

over dt

43:51

etc

43:53

these are all ix because the current

43:55

flows through all of them

43:57

in the same form if they are in series

43:59

they have to have the same current

44:02

now you can see something going on here

44:04

right so we can

44:06

factor i x over d t so we have

44:09

l one plus l two

44:13

et cetera

44:14

d i x

44:16

over d t

44:19

does this equation look familiar we have

44:22

a two-terminal device

44:24

this box here

44:26

whose voltage

44:28

is given by

44:29

the derivative of the current that flows

44:32

through it

44:33

multiplied by some amount so what would

44:36

you call that amount

44:38

that would be the equivalent inductance

44:40

of the circuit right so we say l

44:43

eq

44:45

is equal to l1 plus l2

44:49

etc

44:51

so we see that when inductors are placed

44:53

in series they add

44:55

and that's similar to the case of

44:57

resistors right when resistors are

44:59

placed in series they also add

45:03

okay

45:04

how about inductors in parallel

45:07

so let's

45:09

change the color

45:12

and look at

45:14

inductors

45:18

in

45:20

parallel

45:24

okay so it's the situation we can draw

45:26

it for as many inductors as you want

45:28

let's just try it for two for simplicity

45:34

so two devices in parallel by definition

45:36

must share both of these terminals right

45:39

these terminals are shared oh these

45:41

terminals are shared

45:43

how do i find this inductance same

45:44

method right so we apply a voltage

45:48

vx

45:52

and find this ix

45:55

all right our hope is that the

45:57

relationship between vx and ix it

45:59

resembles that of an inductor

46:04

all right so

46:06

how much is the current to l1

46:09

this current here

46:14

so that's the quiz of the day i will

46:16

give you one minute to think about it

46:18

all right

46:20

[Music]

47:14

all right so what did we get

47:16

well we see that the voltage across l1

47:18

happens to be vx right these are all in

47:20

parallel so if i have the voltage across

47:23

the induction i can find these currents

47:24

right so this current would be

47:26

1 over l1

47:28

integral of vx dt

47:32

similarly this is 1 over l2

47:36

integral of vx dt

47:39

and i know that this current plus this

47:41

current will be equal to i x so i can

47:43

say

47:44

i x

47:46

is equal to

47:47

one over l one

47:50

plus one over l two

47:55

integral of v x d t

48:00

does this equation look familiar

48:03

sure we said that the current inductor

48:05

is equal to one over the inductance

48:08

times the integral of the voltage so

48:11

this has to be one over the inductance

48:13

so we say one over l eq

48:17

is one over l one plus one over l two

48:21

the same equation that we have for

48:23

resistors in parallel so it's similar

48:28

i will see you next time

48:31

[Music]

48:37

so

48:50

you

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